Engineering Board Exam Reviewer · Integration by Substitution · medium

Evaluate: 2/(x3+1)2,dx

1. -1/3(x3+1)+C
2. -1/x3+1+C
3. 1/3(x3+1)+C
4. -3/x3+1+C

Answer

A. -1/3(x3+1)+C

Solution

Let u=x3+1, du=3x2,dx. 13 u-2,du=-1/3u+C=-1/3(x3+1)+C.

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