Engineering Board Exam Reviewer · Integration by Substitution · medium

Evaluate: x2(x3-2)4,dx

1. (x3-2)5/15+C
2. (x3-2)5/5+C
3. (x3-2)4/12+C
4. 5(x3-2)4/3+C

Answer

A. (x3-2)5/15+C

Solution

Let u=x3-2, du=3x2,dx. 13 u4,du= 13·u5/5+C=(x3-2)5/15+C.

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