Engineering Board Exam Reviewer · Integration by Substitution · medium

Evaluate: ≤ft(x ) ≤ft(x ) 4≤ft(x ) + 1,dx

1. ≤ft( 2≤ft(x ) )+C
2. ≤ft( 4≤ft(x ) + 1 )4+C
3. ≤ft( 2≤ft(x ) )4+C
4. ≤ft( 2≤ft(x ) )2+C

Answer

D. ≤ft( 2≤ft(x ) )2+C

Solution

Let u= 2x, du=2 x x,dx. Then x x,dx/1+ 4x= 12 /1+u2= 12 ( 2x)+C.

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