Engineering Board Exam Reviewer · RL Circuits · medium
In the parallel RL circuit shown, a 480 V (rms) source with =1000 rad/s feeds R=96, and L=40 mH in parallel. Find the magnitude of the total impedance seen by the source.
- 28.2,
- 68,
- 104,
- 36.9,
Answer
D. 36.9,
Solution
XL= L=(1000)(40 mH)=40, . IR=V/R= 480 V96, =5 A, IL=V/XL= 480 V40, =12 A. IT=sqrt(IR2+IL2)= (5 A)2+(12 A)2=13 A. |ZT|=V/IT= 480 V13 A=36.9, .
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