Engineering Board Exam Reviewer · RL Circuits · medium
In the series RL circuit shown, a 232 V (rms) source with =500 rad/s is connected to R=84, and L=160 mH. Find the voltage across the inductor.
- 113 V
- 160 V
- 64 V
- 232 V
Answer
B. 160 V
Solution
XL= L=(500)(160 mH)=80, . |Z|=sqrt(R2+XL2)=sqrt((84, )2+(80, )2)=116, . I=V/|Z|= 232 V116, =2 A. VL=IXL=(2 A)(80, )=160 V.
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