Engineering Board Exam Reviewer · RL Circuits · medium
In the series RL circuit shown, a 400 V (rms) source with =5000 rad/s is connected to R=28, and L=19.2 mH. Find the apparent power supplied by the source.
- 1.6 kVA
- 0.448 kVA
- 5.71 kVA
- 3.2 kVA
Answer
A. 1.6 kVA
Solution
XL= L=(5000)(19.2 mH)=96, . |Z|=sqrt(R2+XL2)=sqrt((28, )2+(96, )2)=100, . I=V/|Z|= 400 V100, =4 A. S=VI=(400 V)(4 A)=1.6 kVA.
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