Engineering Board Exam Reviewer · RL Circuits · medium
In the parallel RL circuit shown, a 60 V (rms) source with =10000 rad/s feeds R=40, and L=3 mH in parallel. Find the total current drawn from the source.
- 3.5 A
- 0.5 A
- 2.5 A
- 1.2 A
Answer
C. 2.5 A
Solution
XL= L=(10000)(3 mH)=30, . IR=V/R= 60 V40, =1.5 A, IL=V/XL= 60 V30, =2 A. IT=sqrt(IR2+IL2)= (1.5 A)2+(2 A)2=2.5 A. (Branch currents are 90° apart, so they add as phasors, not arithmetically.)
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