Engineering Board Exam Reviewer · Time Response of Reactive Circuits · medium
The switch in the circuit shown closes at t=0 with the capacitor initially uncharged (V=24 V, R=20 k , C=500 nF). Find the capacitor voltage at t=15 ms.
- 5.36 V
- 12.7 V
- 37.3 V
- 18.6 V
Answer
D. 18.6 V
Solution
=RC=10 ms. vC=V(1-e-t/ )=24 V≤ft(1-e-15 ms/10 ms )=18.6 V.
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