Engineering Board Exam Reviewer · Time Response of Reactive Circuits · hard
The capacitor in the circuit shown already holds 6 V (same polarity as the source) when the switch closes at t=0 (V=24 V, R=10 k , C=10, F). Find the capacitor voltage at t=0.2 s.
- 21.6 V
- 0.812 V
- 8.44 V
- 43.1 V
Answer
A. 21.6 V
Solution
=RC=0.1 s. With a nonzero starting value, vC=V+(V0-V)e-t/ =24+(6-24)e-0.2/0.1=24-18(0.1353)=21.6 V.
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