Engineering Board Exam Reviewer · Time Response of Reactive Circuits · medium
The capacitor shown is charged to 50 V when the switch closes at t=0 and discharges through R=20 k (C=22, F). Find the capacitor voltage at t=440 ms.
- 31.6 V
- 36.8 V
- 9.2 V
- 18.4 V
Answer
D. 18.4 V
Solution
=RC=440 ms. vC=V0e-t/ =50 V,e-440 ms/440 ms=18.4 V.
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