Engineering Board Exam Reviewer · Three-Phase Systems in Power Applications · medium
In the two-wattmeter method on a balanced three-phase load, the wattmeters read 5 kW and 3 kW. What is the load power factor?
- 0.25
- 0.918
- 0.6
- 0.397
Answer
B. 0.918
Solution
= 3,W1-W2/W1+W2= 3,2/8=0.433 =23.4°. PF= 23.4°=0.918 (total power =8 kW).
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