Engineering Board Exam Reviewer · Parallel Circuits · hard
In the circuit shown, the current source supplies I=6 A to the parallel resistors R1=12, , R2=8, , and R3=24, . Find the current through R2.
- 3 A
- 2 A
- 0.67 A
- 6 A
Answer
A. 3 A
Solution
The voltage across the parallel group is V=I,Req with Req=4, , so V=(6 A)(4, )=24 V. Then I2=V/R2= 24 V8, =3 A.
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