Engineering Board Exam Reviewer · Parallel Circuits · medium

In the parallel circuit shown, V=72 V, R1=9, , R2=6, , and R3=18, . Find the total power supplied by the source.

  1. 576 W
  2. 1728 W
  3. 157.09 W
  4. 864 W

Answer

B. 1728 W

Solution

IT= VReq= 72 V3, =24 A, so P=VIT=(72 V)(24 A)=1728 W. This is the sum of the powers in the branches.

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