Engineering Board Exam Reviewer · Parallel Circuits · medium
In the parallel circuit shown, V=72 V, R1=12, , R2=6, , and R3=4, . How much power is dissipated by R1?
- 235.64 W
- 864 W
- 216 W
- 432 W
Answer
D. 432 W
Solution
P=V2/R1= (72 V)212, =432 W.
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