Engineering Board Exam Reviewer · Parallel Circuits · medium

In the circuit shown, the current source supplies I=6 A to the parallel resistors R1=10, and R2=40, . Find the current through R1.

  1. 1.2 A
  2. 3 A
  3. 4.8 A
  4. 9.6 A

Answer

C. 4.8 A

Solution

The voltage across the parallel group is V=I,Req with Req=8, , so V=(6 A)(8, )=48 V. Then I1=V/R1= 48 V10, =4.8 A.

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