Engineering Board Exam Reviewer · Strength of Materials · medium
A steel rod (E = 200 GPa) 20 mm in diameter and 2.5 m long carries an axial tensile load of 60 kN. What is its total elongation?
- 0.597
- 4.775
- 2.387
- 1.194
Answer
C. 2.387
Solution
A = π d2/4 = 314.16 mm2. = PL/(AE) = (60 × 1000 N)(2.5 × 1000 mm) / (314.16 mm2 × 200 × 1000 MPa) = 2.387 mm.
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