Engineering Board Exam Reviewer · Engineering Mechanics · medium
A 19 kg block rests on an incline of 25° with a coefficient of friction of 0.25. What minimum force, applied parallel to the incline, is needed to push the block up the incline at constant velocity?
- 78.77
- 36.54
- 46.6
- 121
Answer
D. 121
Solution
W = mg = 186.39 N. To move up at constant velocity: F = W( + ) = 186.39( 25° + 0.25 25°) = 121 N.
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