Engineering Board Exam Reviewer · Inverse Laplace Transforms · hard

Find the inverse Laplace transform of F(s)=1/s2(s+1).

1. t + 1 - e- t
2. t - 1 + e- t
3. 1 - e- t
4. t - 1 - e- t

Answer

B. t - 1 + e- t

Solution

Partial fractions: 1/s2(s+1)=1/s2-1/s+1/s+1. So f(t)=t-1+e-t.

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