Engineering Board Exam Reviewer · Inverse Laplace Transforms · hard

Find the inverse Laplace transform of F(s)=s/(s2+1)(s2+4).

1. t3 - 2 t3
2. - t3 + 2 t3
3. t - 2 t
4. t3 - 2 t3

Answer

A. t3 - 2 t3

Solution

Partial fractions in s2: 1/(u+1)(u+4)= 13≤ft(1/u+1-1/u+4 ) with u=s2. So F(s)= 13≤ft(s/s2+1-s/s2+4 ) and f(t)= 13( t- 2t).

More Inverse Laplace Transforms questions

1. Find the inverse Laplace transform of F(s)=3/(s+1)(s+4).
2. Find the inverse Laplace transform of F(s)=2s+5/s2+4s+8.
3. Find the inverse Laplace transform of F(s)=s+3/s2+6s+13.
4. Find the inverse Laplace transform of F(s)=1/(s-1)(s-2).
5. Find the inverse Laplace transform of F(s)=4/s3.
6. Find the inverse Laplace transform of F(s)=5/s2+25.
7. Find the inverse Laplace transform of F(s)=1/s-5.
8. Find the inverse Laplace transform of F(s)=3/s2.
9. Find the inverse Laplace transform of F(s)=6/s2+9.
10. Find the inverse Laplace transform of F(s)=s/s2+16.

All Inverse Laplace Transforms questions