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Find the inverse Laplace transform of F(s)=3/(s+1)(s+4).

  1. e- t + e- 4 t
  2. 3 e- t - 3 e- 4 t
  3. - e4 t + et
  4. e- t - e- 4 t

Answer

D. e- t - e- 4 t

Solution

Partial fractions: 3/(s+1)(s+4)=1/s+1-1/s+4. So f(t)=e-t-e-4t.

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