Engineering Board Exam Reviewer · Inverse Laplace Transforms · medium

Find the inverse Laplace transform of F(s)=s+3/s2+6s+13.

1. e3 t 2 t
2. e- 3 t 2 t
3. e- 3 t 2 t
4. e- 3 t sqrt(13) t

Answer

B. e- 3 t 2 t

Solution

Complete the square: s2+6s+13=(s+3)2+4. So F(s)=s+3/(s+3)2+4 and f(t)=e-3t 2t.

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