Engineering Board Exam Reviewer · Rectilinear Motion: Velocity and Acceleration · easy

A particle moves along a line with position s=t3-6t2+9t meters. Find its velocity at t=2 s.

  1. 3 m/s
  2. -3 m/s
  3. -9 m/s
  4. 9 m/s

Answer

B. -3 m/s

Solution

v=ds/dt=3t2-12t+9. At t=2: v=12-24+9=-3 m/s.

More Rectilinear Motion: Velocity and Acceleration questions

  1. A particle's velocity is v=t2-4t+3 m/s. Find its acceleration when its velocity is zero for the second time.
  2. A particle's position is s=t3-6t2+9t meters. Find the total distance traveled during the first 4 seconds.
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  4. A particle's position is s=t3-9t2+24t. At what times is it momentarily at rest?
  5. A particle's position is s=2t3-3t2+t meters. Find its acceleration at t=1 s.

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