Engineering Board Exam Reviewer · Rectilinear Motion: Velocity and Acceleration · easy
A particle's position is s=2t3-3t2+t meters. Find its acceleration at t=1 s.
- 0 m/s2
- 12 m/s2
- 6 m/s2
- -6 m/s2
Answer
C. 6 m/s2
Solution
v=6t2-6t+1 and a=12t-6. At t=1: a=6 m/s2.
More Rectilinear Motion: Velocity and Acceleration questions
- A particle moves along a line with position s=t3-6t2+9t meters. Find its velocity at t=2 s.
- A particle's velocity is v=t2-4t+3 m/s. Find its acceleration when its velocity is zero for the second time.
- A particle's position is s=t3-6t2+9t meters. Find the total distance traveled during the first 4 seconds.
- A ball is thrown upward so that its height is s=40t-5t2 meters. Find the maximum height.
- A particle's position is s=t3-9t2+24t. At what times is it momentarily at rest?