Engineering Board Exam Reviewer · Rectilinear Motion: Velocity and Acceleration · medium
A ball is thrown upward so that its height is s=40t-5t2 meters. Find the maximum height.
- 80 m
- 160 m
- 40 m
- 100 m
Answer
A. 80 m
Solution
v=40-10t=0 t=4 s. Then s(4)=160-80=80 m.
More Rectilinear Motion: Velocity and Acceleration questions
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