Engineering Board Exam Reviewer · Rectilinear Motion: Velocity and Acceleration · hard
A particle's velocity is v=t2-4t+3 m/s. Find its acceleration when its velocity is zero for the second time.
- -2 m/s2
- 0 m/s2
- 2 m/s2
- 6 m/s2
Answer
C. 2 m/s2
Solution
v=(t-1)(t-3)=0 at t=1 and t=3, so the second time is t=3. a=dv/dt=2t-4=2 m/s2.
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