Engineering Board Exam Reviewer · RLC Circuits and Resonance · medium
The curve shows the normalized current of a series RLC circuit versus frequency. The dashed lines mark the half-power (0.707) points, at f1=9.395 kHz and f2=10.645 kHz, and the peak occurs at f0=10 kHz. Find the quality factor of the circuit.
- 0.499
- 8
- 4
- 16
Answer
B. 8
Solution
BW=f2-f1=10.645 kHz-9.395 kHz=1.25 kHz. Q=f0/BW= 10 kHz1.25 kHz=8.
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