Engineering Board Exam Reviewer · RLC Circuits and Resonance · medium
In the series RLC circuit shown, a 52 V (rms) source with =10000 rad/s is connected to R=12, , L=1.5 mH, and C=5, F. Find the voltage across the capacitor.
- 60 V
- 20 V
- 80 V
- 22.1 V
Answer
C. 80 V
Solution
XL= L=(10000)(1.5 mH)=15, and XC=1/ C= 1(10000)(5, F)=20, . The net reactance is X=XL-XC=-5, (capacitive). |Z|=sqrt(R2+(XL-XC)2)=sqrt((12, )2+(5, )2)=13, . I=V/|Z|= 52 V13, =4 A. VC=IXC=(4 A)(20, )=80 V.
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