Engineering Board Exam Reviewer · RLC Circuits and Resonance · medium
In the series RLC circuit shown, a 17 V (rms) source with =5000 rad/s is connected to R=30, , L=12.8 mH, and C=2.5, F. Find the current in the circuit.
- 0.5 A
- 0.567 A
- 0.0977 A
- 0.116 A
Answer
A. 0.5 A
Solution
XL= L=(5000)(12.8 mH)=64, and XC=1/ C= 1(5000)(2.5, F)=80, . The net reactance is X=XL-XC=-16, (capacitive). |Z|=sqrt(R2+(XL-XC)2)=sqrt((30, )2+(16, )2)=34, . I=V/|Z|= 17 V34, =0.5 A.
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