Engineering Board Exam Reviewer · RLC Circuits and Resonance · hard
A series RLC circuit is shown, with R=25, , L=200 mH, and C=5, F connected to a variable-frequency source of 24 V rms. What is the voltage across the capacitor at resonance?
- 24 V
- 136 V
- 192 V
- 384 V
Answer
C. 192 V
Solution
0= 1sqrt(LC)= 1 (200 mH)(5, F)=1000 rad/s, so f0= 0/2π=159 Hz. At resonance I=V/R= 24 V25, =0.96 A and XC=200, . VC=IXC=(0.96 A)(200, )=192 V, which is Q=8 times the source voltage.
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