Engineering Board Exam Reviewer · Circuit Theorems in AC Analysis · hard
In the circuit shown, V1=120 V 0° and V2=100 V -45° (the + marks are at the top), with Z1=20-j50, , Z2=50-j60, , and Z3=60-j50, . Using mesh analysis with both mesh currents I1 (left) and I2 (right) taken clockwise, find I1 in polar form.
- 1.05 -82.1° A
- 1.05 82.1° A
- 0.734 135.5° A
- 0.851 38.3° A
Answer
B. 1.05 82.1° A
Solution
Mesh 1: (Z1+Z2)I1-Z2I2=V1. Mesh 2: -Z2I1+(Z2+Z3)I2=-V2. Solving the two complex equations gives I1=1.05 82.1° A and I2=0.734 135.5° A.
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