Engineering Board Exam Reviewer · Circuit Theorems in AC Analysis · medium
In the circuit shown, a 240 V 0° source feeds a series branch of R1=50, and XL=60, , followed by R2=30, in parallel with a capacitor of reactance XC=30, . Find the magnitude of the current supplied by the source.
- 2.81 A
- 2.42 A
- 3.04 A
- 6.07 A
Answer
C. 3.04 A
Solution
Zp=R2(-jXC)/R2-jXC=15-j15, . ZT=(R1+jXL)+Zp=65+j45, =79.1 34.7°, . |I|=V/|ZT|= 240 V79.1, =3.04 A.
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