Engineering Board Exam Reviewer · Circuit Theorems in AC Analysis · medium
A source of 150 V 0° drives a branch Z1=40-j50, in series with the parallel branch Z2=50+j60, , as shown. Terminals a and b are the open terminals across Z2. Find the magnitude of the Norton (short-circuit) current at terminals a-b.
- 1.66 A
- 1.92 A
- 1.06 A
- 2.34 A
Answer
D. 2.34 A
Solution
Shorting a-b also shorts Z2, so the full source voltage sits across Z1: IN=V/|Z1|= 150 V64, =2.34 A.
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