Engineering Board Exam Reviewer · Circuit Theorems in AC Analysis · hard
In the circuit shown, V1=100 V 0° and V2=80 V -60° (the + marks are at the top), with Z1=40+j50, , Z2=30-j10, , and Z3=80+j10, . Using superposition, find the voltage across Z2 caused by V1 acting alone (with V2 replaced by a short circuit). Give the answer in polar form.
- 29.9 -47.2° V
- 29.9 47.2° V
- 39.2 -48.2° V
- 48.5 -53.4° V
Answer
A. 29.9 -47.2° V
Solution
With V2 shorted, Z2 Z3=22.7-j4.55, and the total impedance is Z1+(Z2 Z3)=62.7+j45.5, . VZ2'=V1Z2 Z3/Z1+(Z2 Z3)=29.9 -47.2° V (the effect of V2 alone is 19 -63° V, and the two add to 48.5 -53.4° V).
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