Engineering Board Exam Reviewer · Circuit Theorems and Conversions · medium
A source V=24 V with internal resistance Rs=15, supplies a variable load RL, as shown. Find the power delivered to the load when RL=30, (that is, RL=2Rs).
- 9.6 W
- 8.53 W
- 19.2 W
- 12.8 W
Answer
B. 8.53 W
Solution
I=V/Rs+RL= 24 V45, =533.33 mA. So PL=I2RL=(533.33 mA)2(30, )=8.53 W. (This is less than the maximum 9.6 W at RL=Rs.)
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