Engineering Board Exam Reviewer · Circuit Theorems and Conversions · medium
In the circuit shown, V1=15 V, V2=30 V, R1=15, , R2=10, , and R3=6, . Use superposition to find the current through R2 (taken positive downward) due to V1 acting alone (V2 replaced by a short circuit).
- 300 mA
- 600 mA
- 800 mA
- 180 mA
Answer
A. 300 mA
Solution
With V2 shorted, R2 R3=3.75, , so IT=V1/R1+R2 R3= 15 V18.75, =800 mA. The current divides: IR2=ITR3/R2+R3=(800 mA)6, /10, +6, =300 mA.
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