Engineering Board Exam Reviewer · Circuit Theorems and Conversions · medium

For the circuit shown, I=10 A, R1=5, , and R2=15, . Find the Norton current IN at terminals a-b.

  1. 2.5 A
  2. 10 A
  3. 7.5 A
  4. 5 A

Answer

A. 2.5 A

Solution

Short terminals a-b. Then R1 and R2 are in parallel across the current source, so the source current divides between them, and IN is the part flowing through R2: IN=IR1/R1+R2=(10 A)5, /5, +15, =2.5 A.

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