Engineering Board Exam Reviewer · Chemistry · hard
What is the boiling point of a 0.5 m aqueous NaCl solution? Assume complete dissociation. (Kb of water = 0.512 ° C/m)
- 100.256 °C
- 100.512 °C
- 99.488 °C
- 100.768 °C
Answer
B. 100.512 °C
Solution
NaCl gives i = 2 particles. Tb = iKb m = 2(0.512)(0.5) = 0.512 ° C Tb = 100.512 ° C.
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