Engineering Board Exam Reviewer · Chemistry · hard
How many mL of 0.25 M NaOH are needed to neutralize 20 mL of 0.1 M H2SO4? (H2SO4 + 2 NaOH Na2SO4 + 2 H2O)
- 8.0 mL
- 4.0 mL
- 20.0 mL
- 16.0 mL
Answer
D. 16.0 mL
Solution
n( H2SO4) = 0.1(0.020) = 0.002 mol n( NaOH) = 0.004 mol. V = 0.004/0.25 = 0.016 L = 16.0 mL.
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