Engineering Board Exam Reviewer · Chemistry · medium

What is the molality of a solution containing 9 g of glucose ( C6H12O6) in 500 g of water? (Use H = 1, C = 12, N = 14, O = 16, Na = 23, S = 32, Cl = 35.5, Ca = 40)

  1. 0.05 m
  2. 18.00 m
  3. 0.01 m
  4. 0.10 m

Answer

D. 0.10 m

Solution

n = 9/180 = 0.05 mol. m = 0.05/0.5 kg = 0.10 mol/kg.

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