Engineering Board Exam Reviewer · Chemistry · medium

What is the pressure exerted by 0.5 mol of gas in a 5 L container at 273 K? (R = 0.08206 L· atm/mol· K)

Answer

C. 2.240 atm

P = nRT/V = 0.5(0.08206)(273)/5 = 2.240 atm.

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