Engineering Board Exam Reviewer · Physics · medium
A force of 50 N is applied tangentially to the rim of a wheel of radius 0.4 m. What torque is produced?
- 125 N· m
- 50 N· m
- 0.008 N· m
- 20 N· m
Answer
D. 20 N· m
Solution
= Fr = 50(0.4) = 20 N· m.
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