Engineering Board Exam Reviewer · Physics · medium
A 0.15 kg ball moving at 40 m/s is hit back in the opposite direction at 50 m/s. What is the magnitude of the impulse on the ball?
- 1.5 kg· m/s
- 6 kg· m/s
- 7.5 kg· m/s
- 13.5 kg· m/s
Answer
D. 13.5 kg· m/s
Solution
J = m(v2 - v1) = 0.15(50 - (-40)) = 0.15(90) = 13.5 kg· m/s.
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