Engineering Board Exam Reviewer · Engineering Mechanics · medium
A 7 kg cart moving at 12 m/s collides with and sticks to a stationary 6 kg cart (a perfectly inelastic collision). What is their common velocity immediately after the collision?
- 14
- 6
- 0.15
- 6.46
Answer
D. 6.46
Solution
By conservation of momentum: m1v1 + m2v2 = (m1+m2)vf. (7)(12) + (6)(0) = (13)vf, so vf = 6.46 m/s.
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