Engineering Board Exam Reviewer · Engineering Mechanics · medium
A 5 kg cart moving at 10 m/s collides with and sticks to a stationary 4 kg cart (a perfectly inelastic collision). What is their common velocity immediately after the collision?
- 12.5
- 5.56
- 5
- 0.18
Answer
B. 5.56
Solution
By conservation of momentum: m1v1 + m2v2 = (m1+m2)vf. (5)(10) + (4)(0) = (9)vf, so vf = 5.56 m/s.
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