Engineering Board Exam Reviewer · Engineering Mechanics · medium
A 2 kg object's velocity increases from 3 m/s to 5 m/s in 0.5 seconds due to a constant applied force. What is the magnitude of that force?
- 20
- 2
- 8
- 8.64
Answer
C. 8
Solution
Impulse = p = m(v2 - v1) = 2(5 - 3) = 4 kg· m/s. Force = Impulse / t = 4 / 0.5 = 8 N.
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