Engineering Board Exam Reviewer · Engineering Mechanics · hard
A 7 kg ball moving at 9 m/s collides with a 6 kg ball moving at -5 m/s (negative indicating the opposite direction). After the collision, the first ball moves at 1 m/s. Using conservation of momentum, what is the velocity of the second ball after the collision?
- 1
- 4.33
- -4.33
- 2.54
Answer
B. 4.33
Solution
Conservation of momentum: m1v1 + m2v2 = m1v1' + m2v2'. (7)(9) + (6)(-5) = (7)(1) + (6)v2'. Solving, v2' = 4.33 m/s.
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