Engineering Board Exam Reviewer · Hyperbolas · medium

For any point on the hyperbola x2/25-y2/144=1, find the absolute difference of its distances from the two foci.

1. 10
2. 5
3. 13
4. 26

Answer

A. 10

Solution

The absolute difference of the focal distances is 2a=2(5)=10.

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1. Find the vertices of the hyperbola (x-1)2/9-(y+2)2/4=1.
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3. Find the length of the latus rectum of the hyperbola x2/9-y2/16=1.
4. Find the equation of the hyperbola with foci at ( 5,0) and a transverse axis of length 6.
5. Find the eccentricity of the hyperbola x2/16-y2/9=1.
6. Find the equations of the asymptotes of the hyperbola x2/16-y2/9=1.
7. Find the foci of the hyperbola x2/16-y2/9=1.
8. Find the length of the transverse axis of the hyperbola x2/16-y2/9=1.
9. Find the distance between the foci of the hyperbola 9x2-16y2-36x-32y-124=0.
10. Find the distance between the two directrices of the hyperbola x2/16-y2/9=1.

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