Engineering Board Exam Reviewer · Hyperbolas · medium
Find the vertices of the hyperbola (x-1)2/9-(y+2)2/4=1.
- (1,1) and (1,-5)
- (3,-2) and (-3,-2)
- (4,2) and (-2,2)
- (4,-2) and (-2,-2)
Answer
D. (4,-2) and (-2,-2)
Solution
The center is (1,-2) and a=3 with a horizontal transverse axis, so the vertices are (1 3,-2).
More Hyperbolas questions
- Find the equation of the hyperbola with vertices at (0, 4) and asymptotes y= 2x.
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- Find the equation of the hyperbola with foci at ( 5,0) and a transverse axis of length 6.
- Find the eccentricity of the hyperbola x2/16-y2/9=1.
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- Find the foci of the hyperbola x2/16-y2/9=1.
- Find the length of the transverse axis of the hyperbola x2/16-y2/9=1.
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- The point P lies on the rectangular hyperbola xy=18 and has x=3. Find its distance from the origin.