Engineering Board Exam Reviewer · Hyperbolas · medium

Find the equation of the hyperbola with vertices at (0, 4) and asymptotes y= 2x.

  1. x216 - y24 = 1
  2. - x264 + y216 = 1
  3. - x24 + y216 = 1
  4. - x216 + y24 = 1

Answer

C. - x24 + y216 = 1

Solution

The transverse axis is vertical with a=4. The asymptotes y= /bx= 2x give b=2. The equation is y2/16-x2/4=1.

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  6. Find the length of the transverse axis of the hyperbola x2/16-y2/9=1.
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