Engineering Board Exam Reviewer · Second-Order Linear Homogeneous Equations · easy
Find the general solution of y''-4y=0.
- y = C1 2 x + C2 2 x
- y = C1 e2 x + C2 e- 2 x
- y = ≤ft(C1 + C2 x ) e2 x
- y = C1 e4 x + C2 e- 4 x
Answer
B. y = C1 e2 x + C2 e- 2 x
Solution
r2-4=0 r= 2, so y=C1e2x+C2e-2x.
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